Nomor 1
[tex] \boxed{\begin{aligned}\sf \lim_{x \to 1} \frac{2x}{3x + 5} &=\sf \frac{2(1)}{3(1) + 5} \\ \sf &=\sf \frac{2}{3 + 5} \\ \sf &= \sf \frac{2}{8} \\ \sf &=\sf \frac{1}{4} \end{aligned}}[/tex]
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Nomor 2
[tex] \boxed{\begin{aligned}\sf \lim_{x \to 2} \frac{ - 3x}{x - 4} &=\sf \frac{ - 3(2)}{2 - 4} \\ \sf &=\sf \frac{ - 6}{ - 2} \\ \sf &= \sf 3\end{aligned}}[/tex]
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Nomor 3
[tex] \boxed{\begin{aligned}\sf \lim_{x \to 3} \frac{x + 2}{2 {x}^{2} + 1 } &=\sf \frac{3 + 2}{2( {3)}^{2} + 1} \\ \sf &=\sf \frac{5}{2(9) + 1} \\ \sf &= \sf \frac{5}{18 + 1} \\ \sf &=\sf \frac{5}{19} \end{aligned}}[/tex]
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Nomor 4
[tex] \boxed{\begin{aligned}\sf \lim_{x \to 3} \: {3x}^{2} - 2x + 2&=\sf 3 {(3)}^{2} - 2(3) + 2 \\ \sf &=\sf 3(9) - 6 + 2\\ \sf &= \sf 27 - 6 + 2\\ \sf &=\sf 23\end{aligned}}[/tex]
Jawab:
1. 1/4
2. 3
3. 5/19
4. 23
Penjelasan dengan langkah-langkah:
Semuanya tidak menghasilkan bentuk tak tentu, masukkan saja.
1.
2(1)/3(1)+5
= 2/8
= 1/4
2.
-3(2)/(2-4)
= -6/-2
= 3
3.
(3+2)/2(3)^2+1
= 5/(18+1)
= 5/19
4.
3(3)^2-2(3)+ 2
= 3(9)-6+2
= 27-6+2
= 21+2
= 23
